timeit函数中的IndentationError

admin

我想测量部分代码的处理时间，为此我使用了timeit函数。但是，它从timeit函数内部返回IndentationError。

这是我的代码；

for stem, result in zip(stem_dirs, result_dirs):

        code_to_measure = '''
        print(stem, '\n', result)
        subprocess.call(['python', './a.py', "--dir_in", stem, "--dir_out", result])
        '''

        proccess_time = timeit.timeit(code_to_measure)
        print(proccess_time)

下面是我得到的错误；

Traceback (most recent call last):
  File "code_test.py", line 115, in <module>
    proccess_time = timeit.timeit(code_to_measure)
  File "/usr/local/lib/python3.6/timeit.py", line 233, in timeit
    return Timer(stmt, setup, timer, globals).timeit(number)
  File "/usr/local/lib/python3.6/timeit.py", line 123, in __init__
    compile(stmtprefix + stmt, dummy_src_name, "exec")
  File "<timeit-src>", line 3
    print(stem, '
    ^
IndentationError: unexpected indent

但是，下面代码中的timeit函数仍然可以正常运行；

# importing the required module 
import timeit 

# code snippet to be executed only once 
mysetup = "from math import sqrt"

# code snippet whose execution time is to be measured 
mycode = ''' 
def example(): 
    mylist = [] 
    for x in range(100): 
        mylist.append(sqrt(x)) 
'''

# timeit statement 
print(timeit.timeit(setup = mysetup, 
                    stmt = mycode, 
                    number = 10000))

以下是代码的输出；

0.002189640999858966

我不太确定如何解决这个问题。如果你对这个问题有任何建议或解决方案，请告诉我。

非常感谢你提前这么做。

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